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Standard XII
Physics
Time Period Independent of Amplitude
Question
The differential equation representing the SHM of a particule is
9
d
2
y
d
t
2
+
4
y
=
0.
The time period of the particle is given by :
3
π
s
e
c
2
π
3
s
e
c
π
3
s
e
c
π
s
e
c
A
π
s
e
c
B
π
3
s
e
c
C
2
π
3
s
e
c
D
3
π
s
e
c
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Solution
Verified by Toppr
The correct option is
D
3
π
s
e
c
The differential equation representing S.H.M of a particle is,
9
d
2
y
d
t
2
+
4
y
=
0
9
a
+
4
y
=
0
a
=
−
4
9
y
ω
2
=
4
9
(
a
=
−
ω
2
y
)
ω
=
√
4
9
=
2
3
2
π
T
=
2
3
T
=
3
π
s
e
c
The correct option is D.
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