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Standard XII
Physics
Question
The phase difference between the velocity and displacement of a particle executing SHM is
π
/
2
radian
2
π
radian
π
radian
zero
A
2
π
radian
B
π
radian
C
zero
D
π
/
2
radian
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Solution
Verified by Toppr
x
=
A
s
i
n
(
ω
t
+
θ
)
v
=
d
x
/
d
t
=
A
ω
c
o
s
(
ω
t
+
θ
)
=
−
A
ω
s
i
n
(
ω
t
+
θ
+
π
/
2
)
since
c
o
s
(
π
/
2
+
x
)
=
−
s
i
n
x
Thus, phase difference is of
π
/
2
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