When KMnO-4- acts as an oxidising agent and ultimately forms -MnO-4- -2- MnO-2- Mn-2- O-3- Mn-2- then the number of electrons transferred in each respectively is-4- 3- 1- 51- 5- 3- 71- 3- 4- 53- 5- 7- 1

Question

When KMnO-4- acts as an oxidising agent and ultimately forms -MnO-4- -2- MnO-2-  Mn-2- O-3- Mn-2- then the number of electrons transferred in each respectively is-4- 3- 1- 51- 5- 3- 71- 3- 4- 53- 5- 7- 1

Toppr Admin · Accepted Answer

KMnO4-1e-x2212-x2212-x2192-MnO4-2-x2212-KMnO4-3e-x2212-x2212-x2192-MnO2KMnO4-4e-x2212-x2212-x2192-Mn2O3KMnO4-5e-x2212-x2212-x2192-Mn2-Option C is correct-

When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{2 -}$ , $M n O_{2}$ , $M n_{2} O_{3}$ , $M n^{2 +}$ , then the number of electrons transferred in each case respectively is:
4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1

${K M n O}_{4} + 1 e - - \to [M n O_{4}]^{2 -}$

${K M n O}_{4} + 3 e - - \to M n O_{2}$

${K M n O}_{4} + 4 e - - \to {M n}_{2} O_{3}$

${K M n O}_{4} + 5 e - - \to {M n}^{2 +}$

Option C is correct.

When KMnO4 acts as an oxidising agent and ultimately forms [MnO4]2−, MnO2, Mn2O3, Mn2+, then the number of electrons transferred in each case respectively is:4, 3, 1, 51, 5, 3, 71, 3, 4, 53, 5, 7, 1

KMnO4+1e−−→[MnO4]2−KMnO4+3e−−→MnO2KMnO4+4e−−→Mn2O3KMnO4+5e−−→Mn2+Option C is correct.

When $K M n O_{4}$ acts as an oxidising agent and ultimately forms $[M n O_{4}]^{2 -}$ , $M n O_{2}$ , $M n_{2} O_{3}$ , $M n^{2 +}$ , then the number of electrons transferred in each case respectively is:
4, 3, 1, 5
1, 5, 3, 7
1, 3, 4, 5
3, 5, 7, 1

${K M n O}_{4} + 1 e - - \to [M n O_{4}]^{2 -}$

${K M n O}_{4} + 3 e - - \to M n O_{2}$

${K M n O}_{4} + 4 e - - \to {M n}_{2} O_{3}$

${K M n O}_{4} + 5 e - - \to {M n}^{2 +}$

Option C is correct.