XY2 dissociates as: XY2(g)⇌XY(g)+Y(g) Initial pressure of XY2 is 600mmHg. The total pressure at equilibrium is 800mmHg. Assuming volume of system to remain constant, the value of Kp is:
50
100
200
400
A
100
B
200
C
400
D
50
Open in App
Solution
Verified by Toppr
XY2 dissociates as:
XY2(g)⇌XY(g)+Y(g)
Initial pressure of XY2 is 600mmHg. The total pressure at equilibrium is 800mmHg.
Let xmmHg of XY2 dissociates to reach equilibrium. xmmHg of XY and xmmHg of Y will be formed at equilibrium. 600−xmmHg of XY2 will be present at equilibrium.
Total pressure =(600−x)+x+x=600+xmmHg
But total pressure =800mmHg
600+x=800 or x=200
Was this answer helpful?
53
Similar Questions
Q1
XY2 dissociates as: XY2(g)⇌XY(g)+Y(g) Initial pressure of XY2 is 600mmHg. The total pressure at equilibrium is 800mmHg. Assuming volume of system to remain constant, the value of Kp is:
View Solution
Q2
XY2 dissociates as XY2(g)⇌XY(g)+Y(g) Initial pressure of XY2 is 600mmHg. The total pressure at equilibrium is 800mmHg.
Assuming volume of system to remain constant, the value of Kp is:
View Solution
Q3
XY2 dissociates as, XY2(g)⇌XY(g)+Y(g) Initial pressure of XY2 is 600mmHg. The total pressure at equilibrium is 800mmHg. Assuming volume of system to remain constant, the value of Kp is:
View Solution
Q4
XY2 dissociates as XY2(g)⇌XY(g)+Y(g) when the initial pressure of XY2 is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.
View Solution
Q5
XY2 dissociates as XY2(g)⇌XY(g)+Y(g) when the initial pressure of XY2 is 600 mm of Hg, the total equilibrium pressure is 800 mm of Hg. FInd the value of Equilibrium constant for the reaction assuming that the volume of the system remains unchanged.