A ball of mass m moving with a speed u undergoes a head-on elastic collision with a ball of mass nm initially at rest. The fraction of the incident energy, transferred to the heavier ball is :
n1+n
n(1+n)2
2n(1+n)2
4n(1+n)2
A
2n(1+n)2
B
n1+n
C
n(1+n)2
D
4n(1+n)2
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Solution
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mv=mv1+nmv2,(Conservationofmeomentum) v−0=v2−v1i.e.,v1=v2−v(e=1) mv=−mv+mv2(1+n)v2=2v1+n K.E.∝mv2 The fraction of the incident energy, transferred to the heavier ball is=nm(2v1+n)2mv2=4n(1+n)2
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