A car travels from A to B a- speed of 20- km- h-1- and returns a speed of 30- km- h-1- The average speed of the car the whole journey is-5- km- h-1-24- km- h-1-25- km- h-1-50- km- h-1-

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Toppr Admin · Accepted Answer

Let distance from A to B be xTime for travel from A to B- x-20Time for travel from B to A- x-30Hence-speed for total distance 2x is- 2xx30-x20-2x-xD7-605x-24 km-hr

A car travels from A to B at a, speed of $20 k m h^{- 1}$ and returns at a speed of $30 k m h^{- 1}$ . The average speed of the car for the whole journey is:
$5 k m h^{- 1}$
$24 k m h^{- 1}$
$25 k m h^{- 1}$
$50 k m h^{- 1}$

Let distance from A to B be x
Time for travel from A to B= x/20
Time for travel from B to A= x/30
Hence,speed for total distance 2x is: $\frac{2 x}{\frac{x}{30} + \frac{x}{20}} = \frac{2 x \times 60}{5 x}$ =24 km\hr

A car travels from A to B at a, speed of 20kmh−1 and returns at a speed of 30kmh−1. The average speed of the car for the whole journey is:5kmh−124kmh−125kmh−150kmh−1

Let distance from A to B be xTime for travel from A to B= x/20Time for travel from B to A= x/30Hence,speed for total distance 2x is: 2xx30+x20=2x×605x=24 km\hr

A car travels from A to B at a, speed of $20 k m h^{- 1}$ and returns at a speed of $30 k m h^{- 1}$ . The average speed of the car for the whole journey is:
$5 k m h^{- 1}$
$24 k m h^{- 1}$
$25 k m h^{- 1}$
$50 k m h^{- 1}$

Let distance from A to B be x
Time for travel from A to B= x/20
Time for travel from B to A= x/30
Hence,speed for total distance 2x is: $\frac{2 x}{\frac{x}{30} + \frac{x}{20}} = \frac{2 x \times 60}{5 x}$ =24 km\hr