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Standard XII
Physics
Question
A particle executing SHM of amplitude
4
c
m
and
T
=
4
s
. The time taken by it to move from positive extreme position to half the amplitude is
1
s
1
3
s
2
3
s
√
3
2
s
A
1
3
s
B
2
3
s
C
√
3
2
s
D
1
s
Open in App
Solution
Verified by Toppr
R.E.F image
W
=
2
π
T
=
2
π
4
=
π
2
Using Phalov diagram
w
t
=
π
3
π
2
(
t
)
=
π
3
⇒
t
=
2
3
s
Ans
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