Calculate the electric potential at the center of the square :
0
k2qs2
k4qs2
k(4√2)qs
k4qs
A
k4qs
B
0
C
k2qs2
D
k4qs2
E
k(4√2)qs
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Solution
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Let the distance between each corner and the center of square be x.
∴s2=x2+x2⟹x=s√2
Potential at the center due to charge at corner 1, V1=kqx=√2kqs
The square is symmetric about its center.
Thus total potential at the center V=4V1=k4√2qs
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