Given, Radius of the cone, $$r = 7\,cm$$
and Height of the cone, $$h = 24\,cm$$.
Let $$l$$ be the slant height of the cone.
Then,
$$l = \sqrt{r^2 + h^2}$$
$$ = \sqrt{7^2 + {24}^2} $$
$$= \sqrt{49 + 576} $$
$$= \sqrt{625} $$
$$\implies$$ $$l= 25\,cm$$.
∴ Curved surface area of the cone$$=\pi r l = \dfrac{22}{7} \times 7 \times 25 = 550\,cm^2$$.
Hence, option $$$$ is corect.