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Standard VII
Maths
Operations on Rational Numbers
Question
Evaluate :
$$ \dfrac{-45}{39} \times \dfrac{-13}{15} $$
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Solution
Verified by Toppr
$$ \dfrac{-45}{39} \times \dfrac{-13}{15} $$
It can be written as
$$ = \dfrac{-45 \times -13}{39 \times 15} $$
By further calculation
$$ = \dfrac{-3 \times -1}{3 \times 1} $$
So we get
$$ = \dfrac{3}{3} $$
$$ = 1 $$
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