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Standard IX
Mathematics
Algebraic Identities
Question
Factorise :
27
x
3
+
y
3
+
z
3
−
9
x
y
z
Open in App
Solution
Verified by Toppr
27
x
3
+
y
3
+
z
3
−
9
x
y
z
=
(
3
x
)
3
+
y
3
+
z
3
−
9
x
y
z
=
(
3
x
)
3
+
y
3
+
z
3
−
3
×
3
x
×
y
×
z
using identity
a
3
+
b
3
+
c
3
−
3
a
b
c
=
(
a
+
b
+
c
)
(
a
2
+
b
2
+
c
2
−
a
b
−
b
c
−
c
a
)
Putting
a
=
3
x
,
b
=
y
,
c
=
z
=
(
3
x
+
y
+
z
)
(
9
x
2
+
y
2
+
z
2
−
3
x
y
−
y
z
−
3
z
x
)
.
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