If a car at rest accelerates uniformly and attains a speed of 72 km/hr in 10 s, then it covers a distance of:
200 m
50 m
100 m
400 m
A
100 m
B
200 m
C
50 m
D
400 m
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Solution
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Given
u=0
v=72 km/h=20 m/s
t=2s
a=v−ut
a=2
s=ut+at22
putting values
s=100m
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