Two points A and B move from rest along a straight line with same acceleration f and f′ respectively. If A takes msec more than B and describes n units more than B in acquiring the same speed then
(f−f′)m2=ff′n
(f′−f)n=12ff′m2
(f+f′)m2=ff′n
12(f+f′)m=ff′n2
A
(f−f′)m2=ff′n
B
(f′−f)n=12ff′m2
C
(f+f′)m2=ff′n
D
12(f+f′)m=ff′n2
Open in App
Solution
Verified by Toppr
v2=2f(d+n)=2f′d
v=f′(t)=(m+t)f
eliminate d and m we get (f′−f)n=12ff′m2
Was this answer helpful?
0
Similar Questions
Q1
Two points A and B move from rest along a straight line with same acceleration f and f′ respectively. If A takes msec more than B and describes n units more than B in acquiring the same speed then
View Solution
Q2
Two particles A and B move from rest along a straight line with constant accelerations f and h respectiely. If A takes m seconds more than B and describes n units more than that of B acquiring the same speed, then
View Solution
Q3
A train A runs from east to west and another train B of the same mass and speed runs from west to east along the equator. A presses the track with a force F1 and B with F2. Then:
View Solution
Q4
Two cars P and Q starts from a point at the same time in a straight line and their positions are represented by xp(t)=at+bt2 and xQ(t)=ft−t2. At what time do the cars have the same velocity?
View Solution
Q5
Two sounds A and B are of same amplitudes, same wave forms but of frequencies F and 2F respectively.