A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12ms−1. If the mass of the ball is 0.15kg, determine the change in momentum of the ball. (Assume linear motion of the ball)
3.6kgm/s
5kgm/s
7kgm/s
3.5kgm/s
A
3.5kgm/s
B
7kgm/s
C
3.6kgm/s
D
5kgm/s
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Solution
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The initial momentum of ball P1=m→v, after batsman hits ball and reverses its direction, momentum of ball P2=−m→v Magnitude of change in momentum Δp=|P2−P1|=|−2m→v|=2m|→v| from data given in question m=0.15kg;|→v|=12m/s ΔP=2×0.15×12=3.6kgm/s
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