A body of mass 'm' and velocity 'u' strikes a wall and rebounds with velocity 'v'. The change in momentum is:
m(v−u)
m(u−v)
−m(v+u)
none of these
A
m(v−u)
B
m(u−v)
C
none of these
D
−m(v+u)
Open in App
Solution
Verified by Toppr
Given : →u=u^x→v=−v^x
Thus change in momentum Δ→P=m(→v−→u)
∴Δ→P=m(−v−u)=−m(u+v)^x
Was this answer helpful?
0
Similar Questions
Q1
A body of mass 'm' and velocity 'u' strikes a wall and rebounds with velocity 'v'. The change in momentum is:
View Solution
Q2
A ball of mass 'm' moves normal to a wall with a velocity 'u' and rebounds with a velocity 'v'. The change in momentum of the ball is (surface of the wall is smooth):
View Solution
Q3
A body of mass M collides against a wall with velocity V and rebounds with the same speed. Its magnitude of change in momentum is:
View Solution
Q4
A body of mass 'M' collides against a wall with a velocity v and retraces its path with the same speed. The change in momentum is (take initial direction of velocity as positive)
View Solution
Q5
In above shown figure, a ball of mass m strike the wall with velocity V and rebounds back with same velocity. Calculate the change in momentum.