A charge Q is divided into two parts of q and Q−q. If the Coulomb repulsion between them when they are separated, is to be maximum, the ratio of Qq should be:
1/2
2
4
1/4
A
2
B
1/4
C
4
D
1/2
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Solution
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Let parts are separated at a distance of 'd'
So repulsion force,
F=kq(Q−q)d2
here, Q and d are constant so for maximum force differentiate the force w.r.t q,
dFdq=kd2(Q−2q)
For maximum force, dFdq=0
kd2(Q−2q)=0
Q−2q=0
Qq=2
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