A charge q is placed at corner of a closed cube the flux related with any face of cube.
Must be q8∈0
May be q∈0
Must be zero
May be zero
A
May be zero
B
Must be zero
C
Must be q8∈0
D
May be q∈0
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Solution
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Charge =q
must be q8ϵ0 because cube has 8 corners hence the charge is partially distributed q8.
Now, using Gauss's law,
the flux ϕ=q8ϵ0
(when ϵ0= permittivity of air =8.854×10−12F/m
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