A gas has a volume of V $$cm^3$$ at $$10^o$$C. If the pressure is doubled, at what temperature will the volume still be V $$cm^3$$?
Correct option is D. $$293^o$$C
$$\dfrac{P_1V_1}{T_1}=\dfrac{P_2V_2}{T_2}$$
$$\dfrac{PV}{283}=\dfrac{2P\times V}{T}$$
$$T=2\times 283$$
$$T=566$$K
$$T=566-273$$
$$T=293^o$$C
Answer option C.