Correct option is B. $$60 \mu A , 60 \mu A$$
Capacitance of capacitor $$C = 20 \mu F$$
$$= 20 \times 10^{-6} F$$
Rate of change of potential is,$$\left(\dfrac{dV}{dt} \right) = 3 v/s$$
$$\implies q = CV$$
$$\implies \dfrac{dq}{dt} = C \dfrac{dV}{dt}$$
$$i_c = 20 \times 10^{-6} \times 3$$
$$= 60 \times 10^{-6} A$$
$$= 60 \mu A$$
As we know that $$i_d = i_C = 60 \mu A$$