A particle moves along the x-axis according to x=A[1+sinωt]. What distance does is travel in time interval from t=0 to t=2.5π/ω?
4 A
5 A
6 A
3 A
A
3 A
B
4 A
C
5 A
D
6 A
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Solution
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t=2.5πω=2.5π(2π/T)=(2.5)(T2) =5(T4) Partieie starts from extreme position and in every T4 time it travels a distance A. So in time t=5(T/4) it will travel a distance 5A.
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