A small block oscillates back and forth on a smooth concave surface of radius R. The time period of small oscillation of the block is :
T=2π√Rg
T=2π√2Rg
T=2π√R2g
none of these
A
none of these
B
T=2π√R2g
C
T=2π√Rg
D
T=2π√2Rg
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Solution
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As this case is similar to a simple pendulum. Here normal reaction works in the place of tension. So,
T=2π√Rg
Analogus to T=2π√lg [simple pendulum]
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