(a)Account for the following:
(i)Acidic character increase from HF to HI.
(ii)There is a large difference between the melting and boiling points of oxygen and sulphur.
(iii) Nitrogen does not form pentahalide.
(b) Draw the structures of the following:
(i) ClF3
(ii) XeF4
(a)(i) Size of halide
ions order F−<Cl−<Br−<I− with increase size negative charge is dispered throughout ions and ions gets
stabilized. Thus acidity order HF<HCl<HBr<HI(ii) Due to present
of vacant d-orbital and combining forms of sulphur (S8) which are not occurs in
oxygen, the cohesive energy of sulphur more than oxygen leading to large
melting point and boiling point
(iii) Due to absent
of d-orbital, nitrogen can not extend its octate to form pentahalide.