At certain temperature (T) if the conductivity of pure water is 5.5×10−7Scm−1, then calculate pH of water at given temperature. Given : λ∞H+=350Scm2sq−1;λ∞OH−∞200Scm2eq−1;λ∞OH−=200Scm2sq−1
6
7
8
5
A
5
B
7
C
8
D
6
Open in App
Solution
Verified by Toppr
Conductivity of pure water = 5.5×10−7Scm−1
λ∞H+=350Scm2sq−1λ∞OH−=200Scm2sq−1
At infinity λ=550Scm2sq−1
αOH−=λλ∘=5.5×10−7550=10−9
pOH=−log(10−9)=9
pH=14−9=5
Was this answer helpful?
1
Similar Questions
Q1
At certain temperature (T) if the conductivity of pure water is 5.5×10−7Scm−1, then calculate pH of water at given temperature. Given : λ∞H+=350Scm2sq−1;λ∞OH−∞200Scm2eq−1;λ∞OH−=200Scm2sq−1
View Solution
Q2
What is dissociation constant of water at 25oC from the following data: Conductivity of H2O=5.8×10−8Scm−1, λ∞H+=350.0 and λ∞OH−=198.0Scm2mol−1
View Solution
Q3
λ∞ of NH4OH at infinite dilution is ______ Scm2mol−1 given λ∞ of OH−=174,λ∞ if Cl−=66 and λ∞ of NH4Cl=130Scm2mol−1
View Solution
Q4
The specific conductance of a saturated solution of AgCl in water is 1.826×10−6Ω−1cm−1 at 25∘C calculate its solubility in water at 25∘C. Given that :- λ∘(Ag+)=61.92 λ∘(Cl−)=76.34
View Solution
Q5
At 298K, the conductivity of a saturated solution of AgCl in water is 2.6×10−6Scm−1. Its solubility product at 298K is: