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Question

Calculate the resulting force, if a steel ball of radius 6 cm is immersed in water.

A
7.67 N
B
6.54 N
C
8.87 N
D
9 N
Solution
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Correct option is C. 8.87 N
Given, Radius of steel ball = 6 cm = 0.06 m
Volume of steel ball, $$V = 43r^3$$
$$V = 430.063$$
$$V = 9.05 10^(-4) m^3$$
Density of water, $$ = 1000 kg.m^-3$$
Acceleration due to gravity, $$g = 9.8 m.s^-2$$
From Archimedes principle formula,
$$F_b$$ = g V
$$F_b$$ = $$(1000 kg.m^-3)(9.8 m.s^-2)(9.05 10^-4 m^3)$$
$$F_b$$ = 8.87 N
Hence, option $$C$$ is correct

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