Determine the greatest $$3$$-digit number exactly divisible by $$8$$, $$10$$ and $$12$$.
LCM of $$8, 10$$ and $$12$$
LCM$$=2\times 2\times 2\times 3\times 5=120$$
We have to find the greatest $$3$$-digit multiple of $$120$$.
It can be seen that $$120\times 8=960$$ and $$120\times 9=1080$$.
Hence, the greatest $$3$$-digit number exactly divisible by $$8, 10$$ and $$12$$ is $$960$$.