Find the distance between the centre of gravity and centre of mass of a two-particle system attached to the ends of a light rod. Each particle has the same mass. Length of the rod is R, where R is the radius of the earth.
R
R2
zero
R4
A
R4
B
R2
C
R
D
zero
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Solution
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The centre of gravity of the Earth lie at its centre (Point p in picture)
The centre of mass of the rod is mR+m.02m=R2
The distance between CM of the rod and CG of the Earth is=R2 [PS=R2 in the picture]
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