Find the general solution of the congruence
98x−1≡0(mod.139).
The congruence 98x−1=0(mod 139)
means that 98x−1 is divisible by 139
If y is the quotient, then 98x−1=139y, or 98x−139y=1
If 13998 is converted into a continued fraction the convergent just preceding the fraction is 6143.
Hence, the general solution of the equation is
x=61+139t,y=43+98t