H2(g)+12O2(g)→H2O(l),ΔH=−286kJ...........(iii) On adding the equation as (ii)+2×(iii) we get C(s)+2H2(g)+2O2(g)→CO2(g)+2H2O(l)⇒−394+2×(−286)=−966kJ.........(iv)
From the following data of heats of combustion, find the heat of formation of CH3OH(l)
CH3OH(l)+32O2(g)→CO2(g)+2H2O(l);△rH⊖=−726kJ
C(s)+O2(g)→CO2(g),ΔH=−394kJ
H2(g)+12O2(g)→H2O(l),ΔH=−286kJ
View Solution
Q2
From the following data of heats of combustion, find the heat of formation of CH3OH(l): CH3OH(l)+32O2(g)⟶CO2(g)+2H2O(l);ΔH=−726kJ C(s)+O2(g)⟶CO2(g);ΔH=−394kJ H2(g)+12O2(g)⟶H2O(l);ΔH=−286kJ
View Solution
Q3
Given that, C(s)+O2(g)→CO2(g);ΔH=−394kJ 2H2(g)+O2(g)→2H2O(l);ΔH=−568kJ CH4(g)+2O2(g)→CO2(g)+2H2O(l);ΔH=−394kJ Heat of formation of CH4 is :
View Solution
Q4
Using the following thermochemical data C(S)+O2(g)→CO2(g), ΔH=−94.0Kcal H2(g)+12O2(g)→H2O(l), ΔH=−68.0Kcal CH3COOH(l)+2O2(g)→2CO2(g)+2H2O(l), ΔH=−210.0Kcal The heat of formation of acetic acid is
View Solution
Q5
Calculate the heat of formation of acetic acid from the following data: a. C(s)+O2(g)⟶CO2(g), ΔH=−393.7kJ b. H2(g)+1/2O2(g)⟶H2O(l), ΔH=−285.8kJ c. CH3COOH(l)+2O2(g)⟶2CO2(g)+2H2O(l), ΔH=−873.2kJ