If the series limit wavelength of the Lyman series for hydrogen atom is 912˚A, then the series limit wavelength for the Balmer series for the hydrogen atom is
912˚A/2
912˚A
912×2˚A
912×4˚A
A
912˚A/2
B
912×2˚A
C
912˚A
D
912×4˚A
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Solution
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Series Limit of Balmer series n=1 1λ=R(1n2)=R
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