In a photoelectric experiment the stopping potential for the incident light of wavelength 4000˚A is 2 volt. If the wavelength be changed to 3000˚A, the stopping potential will be :
2 V
Zero
Less than 2 V
More than 2 V
A
2 V
B
Less than 2 V
C
More than 2 V
D
Zero
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Solution
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Photoelectric Effect,
KEmax=hv−Wo
The stopping potential,
Vse=KEmax
Vse=hv−Wo
Vse=hcλ−Wo
From the above equation, as λ decreases, Vs increases. Hence Vs>2V
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