Question

$K$ takes $30$ minutes less time than $M$ to travel a distance of $30km.K$ travels $\frac{1}{3}$ km per hour faster than $M$. If $x$ is $K^{\prime }s$ rate of speed in km per hour, then $K^{\prime }s$ time for the distance is

• A. $\frac{x-\left(1/3\right)}{30}$
• B. $\frac{30}{x+\left(1/3\right)}$
• C. $\frac{30}{x}$
• D. $\frac{x}{30}$
• E. $\frac{x+\left(1/3\right)}{30}$

Answer 1

Answer: (C)

$Time=distance/rate;\therefore t=30/x$.