Refer to teh circuit shown. What will be the total power dissipation in the circuit if P is the power dissipated in R1? It is given that R2=4R1 and R3=12R1
4P
7P
13P
17P
A
7P
B
13P
C
4P
D
17P
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Solution
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Total equivalent resistance=R2R3R2+R3+R1=48R1216R1+R1=3R1+R1=4R1
Power dissipation at R1=I2R1=P
∴ Power dissipation in the total circuit=I24R1
=4I2R1
=4P
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