10mL of a solution of NaOH is found to be completely neutralised by 8mL of a given solution of HCl. If we take 20mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be:
4mL
8mL
12mL
16mL
A
12mL
B
16mL
C
4mL
D
8mL
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Solution
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The correct option is D16mL Reaction of HCl and NaOH is:
NaOH+HCl→NaCl+H2O
1mol of NaOH is neutralized by 1mol of HCl. If
10ml of NaOH is neutralize by HCl=8ml
1ml of NaOH will neutralize by HCl=810ml
20ml of NaOH for neutralization will require HCl=0.8×20ml=16ml
So, the correct option is D
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Q1
10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralise it will be
(a) 4 mL (b) 8mL (c) 12 mL (d) 16 mL
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Q2
Question 3
10 mL of a solution of NaOH is found to be completely neutralized by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount of HCl solution (the same solution as before) required to neutralize it will be:
1. 4 mL
2. 8 mL
3. 12 mL
4. 16 mL