A parallel plate air capacitor has a capacitance $C$ . When it is half filled with a dielectric of dielectric constant $5$ , the percentage increase in the capacitance will be

Question

A parallel plate air capacitor has a capacitance C- When it is half filled with a dielectric of dielectric constant 5- the percentage increase in the capacitance will be-400-66-6-33-3-200-

Toppr Admin · Accepted Answer

C-A-x3F5-0dC1-KC-5C-A-x3F5-0Kd-increase-5C-x2212-CC-xD7-100-400-

A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be:
400%
66.6%
33.3%
200%

$C = \frac{A ϵ_{0}}{d} C^{1} = K C = 5 C = \frac{A ϵ_{0} K}{d} % i n c r e a s e = (\frac{5 C - C}{C}) \times 100 = 400 %$

A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be:400%66.6%33.3%200%

C=Aϵ0dC1=KC=5C=Aϵ0Kd%increase=(5C−CC)×100=400%

A parallel plate air capacitor has a capacitance C. When it is half filled with a dielectric of dielectric constant 5, the percentage increase in the capacitance will be:
400%
66.6%
33.3%
200%

$C = \frac{A ϵ_{0}}{d} C^{1} = K C = 5 C = \frac{A ϵ_{0} K}{d} % i n c r e a s e = (\frac{5 C - C}{C}) \times 100 = 400 %$