At 373 K, steam and water are in equilibrium and ΔH = 40.98 kJ mol−1.What will be ΔS fro conversion of water into steam? H2O(l)→H2O(g)
109.8 J K−1mol−1
31 J K−1mol−1
21.98 J K−1mol−1
326 J K−1mol−1
A
21.98 J K−1mol−1
B
326 J K−1mol−1
C
31 J K−1mol−1
D
109.8 J K−1mol−1
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Solution
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The correct option is A 109.8 J K−1mol−1 The given reaction is :-
H2O(l)⟶H2O(g)
So, we have
△Svap=△HvapTb
=40.98×1000373=109.8JK−1mol−1
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