Construct the right angled $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.
To construct: A right angled $$\triangle {PQR}$$ where $$m\angle {Q}={90}^{o}$$, $$QR=8cm$$ and $$PR=10cm$$.
Steps of construction:
(a) Draw a line segment $$QR=8cm$$
(b) At point $$Q$$, draw $$QX\bot QR$$
(c) Taking $$R$$ as centre, draw an arc of radius $$10cm$$
(d) This arc cuts $$QX$$ at point $$P$$
(e) Join $$PQ$$
It is the required right angled triangle $$PQR$$