Find the height above the surface of the earth where weight of a body becomes half.
(√2−1)R
R2
R(√2+1)
R√2
A
R(√2+1)
B
R√2
C
R2
D
(√2−1)R
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Solution
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Given, weight of the body becomes half.
Let that height be h.
mg2=GMm(R+h)2
And, g=GM(R)2⇒12=1(1+hR)2
Hence, h=(√2−1)R
Multiplying numerator and denominator by √2+1
h=R√2+1
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