From a solid right circular cylinder with height h and radius of the base r, a right circular cone of the same height and same base is removed. Find the volume of the remaining solid.
23πr2h
πr2h
2πr2h
13πr2h
A
2πr2h
B
πr2h
C
23πr2h
D
13πr2h
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Solution
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Volume of the remaining solid = Volume of cylindrical section − Volume of conical shape.
So, Volume of the material removed =πr2h−13πr2h=23πr2h
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