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Standard XII
Physics
Dimensional Analysis
Question
If pressure
P
, area
A
and length
L
are taken to be fundamental quantities in a system of units, then energy has dimensional formula.
P
1
A
1
L
1
P
1
A
0
L
3
P
1
A
3
/
2
L
0
Cannot take
P
,
A
and
L
as fundamental quantities
A
P
1
A
1
L
1
B
P
1
A
3
/
2
L
0
C
Cannot take
P
,
A
and
L
as fundamental quantities
D
P
1
A
0
L
3
Open in App
Solution
Verified by Toppr
We know that
P
=
P
A
=
M
L
T
−
2
L
2
=
M
L
−
1
T
−
2
A
=
L
2
L
=
L
Let
E
=
P
x
A
y
L
z
E
=
M
L
2
T
−
2
=
(
M
L
−
1
T
−
2
)
x
(
L
2
)
y
(
L
)
2
=
M
x
L
−
x
+
2
y
+
z
T
−
2
x
x
=
1
,
−
2
x
=
−
2
x
=
1
−
x
+
2
y
+
z
=
2
z
=
0
,
2
y
=
2
+
1
y
=
3
2
∴
E
=
P
1
A
3
/
2
L
0
.
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