One hundred identical coins each with probability p of showing up heads are tossed once. If
0<p<1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then find the value of p.
Open in App
Solution
Verified by Toppr
We have 100C50p50(1−p)50=100C51p51(1−p)49
or 1−pp=100!51!49!×50!50!100!=5051
⇒51−51p=50p
⇒51=50p+51p
⇒101p=51
∴p=51101
Was this answer helpful?
0
Similar Questions
Q1
One hundred identical coins each with probability p of showing up heads are tossed once. If
0<p<1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then find the value of p.
View Solution
Q2
One hundred identical coins , each with probability, p, of showing up heads are tossed once. If 0<p<1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is:
View Solution
Q3
One-hundred identical coins, each with probability, p, of showing up heads are tossed once. If 0 < p < 1 and the probability of heads showing on 50 coins is equal to that of heads showing on 51 coins, then the value of p is