Prove that:
$$\dfrac {\tan \left(\dfrac {\pi}{2}-x \right) \sec (\pi -x) \sin (-x)}{\sin (\pi +x) \cot (2\pi -x) \csc \left (\dfrac {\pi}{2}-x \right)}=1$$

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Prove that

(i)

\frac{\cos (2 π + x) cosec (2 π + x) \tan (π / 2 + x)}{\sec (π / 2 + x) \cos x \cot (π + x)} = 1

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\frac{\tan (90 ° - x) \sec (180 ° - x) \sin (- x)}{\sin (180 ° + x) \cot (360 ° - x) cosec (90 ° - x)} = 1

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Prove that:$$\dfrac {\tan \left(\dfrac {\pi}{2}-x \right) \sec (\pi -x) \sin (-x)}{\sin (\pi +x) \cot (2\pi -x) \csc \left (\dfrac {\pi}{2}-x \right)}=1$$