Solve the equation:-
limx→π/2 tan 2xx−π/2
limx→π2tan2xx−π2
LHL=limh→0−tan2(π2−h)π2−h−π2
=limh→0−tan(π−2h)−h
=limh→0−−tan2h−h
=limh→0−−2tan2h−2h=2
RHL=limh→0+tan2(π2+h)π2+h−π2
=limh→0+tan(π+2h)h
=limh→0+tan2hh
=limh→0+2tan2h2h=2
Thus,limx→π2tan2xx−π2=2