The electric potential O is -displaystyle frac-sqrt2 q-pi varepsilon-0 a-displaystyle frac-q-pi varepsilon-0 a-displaystyle frac-sqrt3 q-pi varepsilon-0 a-zero

Question

Toppr Admin · Accepted Answer

Here AO-BO-CO-DO-r-x221A-a-2-2-a-2-2-a-x221A-2As the electric potential is a scalar quantity so the potential at O is V-14-x3C0-x3F5-0-qr-qr-x2212-qr-x2212-qr-0

The electric potential at O is :
$\frac{\sqrt{2} q}{π ε_{0} a}$
$\frac{q}{π ε_{0} a}$
$\frac{\sqrt{3} q}{π ε_{0} a}$
zero

Here $A O = B O = C O = D O = r = \sqrt{(a / 2)^{2} + (a / 2)^{2}} = \frac{a}{\sqrt{2}}$
As the electric potential is a scalar quantity so the potential at O is
$V = \frac{1}{4 π ϵ_{0}} [\frac{q}{r} + \frac{q}{r} + \frac{- q}{r} + \frac{- q}{r}] = 0$

The electric potential at O is :√2qπε0aqπε0a√3qπε0azero

Here AO=BO=CO=DO=r=√(a/2)2+(a/2)2=a√2As the electric potential is a scalar quantity so the potential at O is V=14πϵ0[qr+qr+−qr+−qr]=0

The electric potential at O is :
$\frac{\sqrt{2} q}{π ε_{0} a}$
$\frac{q}{π ε_{0} a}$
$\frac{\sqrt{3} q}{π ε_{0} a}$
zero

Here $A O = B O = C O = D O = r = \sqrt{(a / 2)^{2} + (a / 2)^{2}} = \frac{a}{\sqrt{2}}$
As the electric potential is a scalar quantity so the potential at O is
$V = \frac{1}{4 π ϵ_{0}} [\frac{q}{r} + \frac{q}{r} + \frac{- q}{r} + \frac{- q}{r}] = 0$