Water in a rectangular reservoir having base 80m by 60m is 6-5m deep- In what time can the water be emptied by a pipe of which the cross-section is a square of side 20cm- the water runs through the pipe the rate of 15km-hr-

Question

Toppr Admin · Accepted Answer

Let the reservoir be emptied out in -t- hours- Then-cfrac-20-100-times -cfrac-20-100-times 15000-times t-80-times 60-times 6-5-Rightarrow- -t-52- hours-

Water in a rectangular reservoir having base $$80m$$ by $$60m$$ is $$6.5m$$ deep. In what time can the water be emptied by a pipe of which the cross-section is a square of side $$20cm$$, if the water runs through the pipe at the rate of $$15km/hr$$?

Let the reservoir be emptied out in $$t$$ hours. Then
$$\cfrac{20}{100}\times \cfrac{20}{100}\times 15000\times t=80\times 60\times 6.5$$
$$\Rightarrow$$ $$t=52$$ hours.

Water in a rectangular reservoir having base $$80m$$ by $$60m$$ is $$6.5m$$ deep. In what time can the water be emptied by a pipe of which the cross-section is a square of side $$20cm$$, if the water runs through the pipe at the rate of $$15km/hr$$?

Let the reservoir be emptied out in $$t$$ hours. Then$$\cfrac{20}{100}\times \cfrac{20}{100}\times 15000\times t=80\times 60\times 6.5$$$$\Rightarrow$$ $$t=52$$ hours.

Let the reservoir be emptied out in $$t$$ hours. Then
$$\cfrac{20}{100}\times \cfrac{20}{100}\times 15000\times t=80\times 60\times 6.5$$
$$\Rightarrow$$ $$t=52$$ hours.