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Standard XII
Mathematics
Question
(
sin
50
∘
cos
40
∘
)
2
+
(
cos
28
∘
sin
62
∘
)
2
−
2
tan
2
45
∘
0
1
2
1
−
2
A
0
B
−
2
C
1
2
D
1
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Solution
Verified by Toppr
(
sin
50
∘
cos
40
∘
)
2
+
(
cos
28
∘
sin
62
∘
)
2
−
2
tan
2
45
∘
=
(
sin
(
90
−
40
)
∘
cos
40
∘
)
2
+
(
cos
28
∘
sin
(
90
−
28
)
∘
)
2
−
2
tan
2
45
∘
=
(
cos
40
∘
cos
40
∘
)
2
+
(
cos
28
∘
cos
28
∘
)
2
−
2
tan
2
45
∘
=
1
+
1
−
2
(
1
)
2
=
0
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Similar Questions
Q1
(
sin
50
∘
cos
40
∘
)
2
+
(
cos
28
∘
sin
62
∘
)
2
−
2
tan
2
45
∘
View Solution
Q2
Solve:
cos
40
∘
sin
50
∘
−
1
2
(
cos
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∘
sin
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∘
)
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Q3
Solve
sin
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)
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)
+
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tan
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tan
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tan
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tan
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tan
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=
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View Solution
Q4
cos
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∘
+
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)
−
sin
(
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∘
−
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)
=
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Q5
s
i
n
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)
−
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)
=
?
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