In the figure PQRS is a cyclic quadrilateral. If the area of the shaded part is 727sq. units then find the radius of the circle.
2 units
√7 units
4 units
3 units
A
4 units
B
2 units
C
√7 units
D
3 units
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Solution
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R.E.F. Image.
Area of should part.
A=πr2−a2=727 sq. unit
Putting the value of a
πr2−(2r√2)2=727
227.r2−4r22=727
22r2−14r27=727
8r2=72
r2=9
r = 3 unit
Circle Area =πr2
square Area =a2
d = 2r
a=d√2
a=2r√2 [Δ QRS. d2=a2+a2(2r)2=2a2a=2r√2]
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