Then, the circumference:
2πr=44 m.
⟹ r=442π=44×72×22=7m.
Let the slant height be l meters.
Then,
l=√h2+r2=√72+242=√625=25m.
Now, Surface area = πrl=227×7×25=550m2.
∴ Area of canvas required =550 m2.
Given that width of the canvas is 2 m.
Therefore, Length of canvas required = 5502=275m.