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Standard XII
Chemistry
Solubility Product
Question
The solubility of AgCl(s) with solubility product
1.6
×
10
−
10
in 0.1 M NaCl solution would be :
1.6
×
10
−
11
M
1.26
×
10
−
5
M
1.6
×
10
−
9
M
zero
A
1.26
×
10
−
5
M
B
zero
C
1.6
×
10
−
9
M
D
1.6
×
10
−
11
M
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Solution
Verified by Toppr
A
g
C
l
⇌
A
g
+
+
C
l
−
a 0 0
a-S S S+0.1
k
s
p
=
1.6
×
10
−
10
=
[
A
g
+
]
[
C
l
−
]
=
S
(
0.1
+
S
)
k
s
p
is value seems to be very small
S value can be ignored, with respect to 0.1 M
1.6
×
10
−
10
=
S
×
0.1
S
=
1.6
×
10
−
9
M
Hence option D is correct.
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