A dice is rolled twice. Find the probability that (i) 5 will not come up either time. (ii) 5 will
come up exactly one time.
Total event =6×6=36
Events of getting 5 are =(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(1,5),(2,5),(3,5),(4,5),(6,5)
probability of getting getting 5=1136
Probability of not getting 5=1−1136=2536
probability of getting 5 exactly one time is =1036