An electric dipole is placed at an angle of 30o with an electric field intensity 2×105N/C. It experiences a torque equal to 4Nm. The charge on the dipole, if the dipole length is 2cm, is :
7μC
8mC
2mC
5μC
A
7μC
B
2mC
C
8mC
D
5μC
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Solution
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Step 1: Dipole moment of dipole
Given the dipole length l=2cm=2/100m
So, the Dipole moment of dipole will be
P=lq=(2/100)q
P=0.02q
Step 2: Torque acting on dipole
→τ=→P×→E
⇒τ=PEsinθ
Or, 4Nm=(0.02q)(2×105N/C)sin30o
Or, q=200×10−5C=2mC
Hence, Option C is correct
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